5p^2-30p+25=0

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Solution for 5p^2-30p+25=0 equation: 



5p^2-30p+25=0

a = 5; b = -30; c = +25;
Δ = b2-4ac
Δ = -302-4·5·25
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-20}{2*5}=\frac{10}{10}
=1
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+20}{2*5}=\frac{50}{10}
=5
$

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